Question

A body falling from a high Minaret travels 40 meters in the last 2 seconds of its fall to ground. Height of Minaret in meters is (take g=10 $m/s^2$)

• A. 60
• B. 45
• C. 80
• D. 50

Answer 1

The correct option is B 45

Let height of minarate is H nad bodt take T to fall from top to bottom.

$H=\frac{1}{2}g{T}^2...\left(i\right)$
In last 2 sec,body travels distance of 40 metres so in (T-2)sec distance
travelled =(H-40)m.
$(H-40)=\frac{1}{2}g(T-2{)}^2...(ii)$
By solving (i) and (ii) T=3 sec and H=45 m.