Question

A body falling from the rest has a velocity v after it fall through a height h. The distance it has to fall down further for its velocity to become double, will be

• A. 8 h
• B. 6 h
• C. 3 h
• D. 5 h

Answer 1

The correct option is C 3 h

Distance to be fallen from $starting$ point to get velocity $v$ is $h=\frac{v^2}{2g}$

$Similarly$,

the distance to be fallen from $STARTING$ point to get velocity $2v$ is $H=\frac{(2v{)}^2}{2g}=4\times \frac{v^2}{2g}=4\times h=4h$

so the further distance $after$ achieving $v$ will be $H-h=4h-h=3h$