A body falls freely for 10 sec. It's avg velocity during this journey is? ( g= 10 m per s square)

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Solution

Average velocity = (v+u)/2
v= u +at
u =0, a=10m/s^2, t=10s
therefore v=at=10*10=100m/s
Average velocity=(v+u)/2
= (100+0)/2
=50m/s

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A body falls freely for 10 sec. It's avg velocity during this journey is? ( g= 10 m per s square)

Average velocity = (v+u)/2 v= u +at ​​​​u =0, a=10m/s^2, t=10s therefore v=at=10*10=100m/s Average velocity=(v+u)/2 = (100+0)/2 =50m/s

Average velocity = (v+u)/2
v= u +at
u =0, a=10m/s^2, t=10s
therefore v=at=10*10=100m/s
Average velocity=(v+u)/2
= (100+0)/2
=50m/s