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Question

A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time of (Neglect air friction and take g=10 m/s2)

A
3 s
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B
5 s
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C
7 s
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D
9 s
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Solution

The correct option is B 5 s
Distance travelled in the nth second =u+g2(2n1)

Distance travelled in the first 3 seconds:
=ut+12gt2
=0×3+12×10×32=45 m

Distance travelled in last second = Sn=45=5(2n1)n=5

Hence, the body has fallen for a time of 5 s.

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