A body falls from a height of $16 m$ and rebounds to a height of $4 m$ . The coefficient of restitution is

\frac{1}{4}

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\frac{1}{2}

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\frac{3}{4}

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\frac{1}{8}

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Solution

The correct option is A $\frac{1}{2}$
Formula:

$v + L u = 0$

$\Rightarrow L = - \frac{v}{u}$

$\Rightarrow L = \frac{\sqrt{2 g h_{2}}}{\sqrt{2 g h_{1}}}$

$= - \frac{\sqrt{2 \times 9.8 \times 4}}{\sqrt{2 \times 9.8 \times 16}}$

The coefficient of restitution,

$∴ L = \frac{1}{2}$

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A body falls from a height of 16 m and rebounds to a height of 4 m. The coefficient of restitution is

The correct option is A 12Formula:v+Lu=0⇒L=−vu⇒L=√2gh2√2gh1=−√2×9.8×4√2×9.8×16The coefficient of restitution,∴L=12

A body falls from a height of $16 m$ and rebounds to a height of $4 m$ . The coefficient of restitution is

The correct option is A $\frac{1}{2}$
Formula:

$v + L u = 0$

$\Rightarrow L = - \frac{v}{u}$

$\Rightarrow L = \frac{\sqrt{2 g h_{2}}}{\sqrt{2 g h_{1}}}$

$= - \frac{\sqrt{2 \times 9.8 \times 4}}{\sqrt{2 \times 9.8 \times 16}}$

The coefficient of restitution,

$∴ L = \frac{1}{2}$