A body falls from a height of $45$ m above the ground. Find the time taken by the body to reach the ground. $(T a k e g = 10 {m s}^{- 2})$

5

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Solution

The correct option is C $3$ s
Initial speed $u = 0 m / s$
Acceleration $a = g = 10 m / s^{2}$
Height $h = 45 m$
Using $h = u t + \frac{1}{2} a t^{2}$
Or $45 = 0 + \frac{1}{2} (10) t^{2}$
$⟹ t = 3 s$

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