A body falls from a height of 500 m. In how much time, will it strike the ground ? (Give the answer in seconds)

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Solution

Here,

Initial velocity, $u = 0$
Distance covered, $S = 500m$
Acceleration due to gravity, $g = {10 m s}^{- 2}$
Step 1: Time taken:
From 2nd equation of motion,
$s = u t + \frac{1}{2} a t^{2} ⟹ 500 = 0 + \frac{1}{2} \times 10 \times t^{2}$
$t^{2} = \frac{500}{5}$
$t^{2} = 100$
$t = 10 s$
Hence, it will strike the ground, after
$t = 10 s$

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A body falls from a height of 500 m. In how much time, will it strike the ground ? (Give the answer in seconds)

Here, Initial velocity, u = 0 Distance covered, S = 500m Acceleration due to gravity, g=10ms−2 Step 1: Time taken:From 2nd equation of motion,s=ut+12at2⟹500=0+12×10×t2t2=5005 t2=100 t=10s Hence, it will strike the ground, after t=10s