A body floats in a liquid contained in a beaker. The whole system as shown in the figure falls freely under gravity. The upthrust on the body is

zero.

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equal to the weight of the liquid displaced.

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equal to the weight of the body in air.

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equal to the weight of the immersed portion of the body.

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Solution

The correct option is A zero.
When the beaker is allowed to fall freely, apparent weight of the body becomes zero i.e. body exerts no force on water. Hence no water is displaced due to weight of the body. So buoyant force i.e. upthrust will also become zero.

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A body of volume V and density $ρ$ is kept completely immersed in a liquid of density $ρ_{L}$ . If g is the acceleration due to gravity, write expressions for the following :
(i) Weight of the body
(ii) The upthrust on the body
(iii) Apparent weight of the body in the liquid
(iv) The loss in weight of the body

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A body floats in a liquid contained in a beaker. The whole system as shown in the figure falls freely under gravity. The upthrust on the body is

The correct option is A zero.When the beaker is allowed to fall freely, apparent weight of the body becomes zero i.e. body exerts no force on water. Hence no water is displaced due to weight of the body. So buoyant force i.e. upthrust will also become zero.

The correct option is A zero.
When the beaker is allowed to fall freely, apparent weight of the body becomes zero i.e. body exerts no force on water. Hence no water is displaced due to weight of the body. So buoyant force i.e. upthrust will also become zero.