A body floats with 2/5 th of its volume above the surface of water. Calculate the density of the material of the body in gcm^gcm-3

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Solution

Let volume of block be V and density of meterial be d.

Volume of block immersed = 3/5 V

By the principle of flotation,

Weight of the block = Weight of the water displaced by the immersed part of the block

i.e., V × d× g = 3/5 V× 1 ×g

d = 3/5

= 0.6 g cm^–3

(Here the density of water is taken as 1 g cm^–3).

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Let volume of block be V and density of meterial be d.
Volume of block immersed	=	3/5 V

By the principle of flotation,
Weight of the block	=	Weight of the water displaced by the immersed part of the block
i.e., V × d× g	=	3/5 V× 1 ×g
d	=	3/5
	=	0.6 g cm^–3
(Here the density of water is taken as 1 g cm^–3).