A body goes to $10 k m$ north and $20 k m$ east. The displacement from initial point is

22.36 k m

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2 k m

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5 k m

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20 k m

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Solution

The correct option is A $22.36 k m$
Total displacement will be the hypotenuse of two north and east sides.
$s = \sqrt{10^{2} + 20^{2}} = \sqrt{100 + 400} = \sqrt{500} = 22.36 k m$

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