A body hangs from a spring balance supported from the roof of the elevator, the balance reads $50 N$ when the elevator has an upward acceleration of $2.5 {m/s}^{2}$ . What is the true weight of the body? $($ Take $g$ = $10 {m/s}^{2})$

20 N

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30 N

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40 N

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60 N

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Solution

The correct option is C $40 N$

Due to psuedo force $T = m g + m a$
Given, $T = 50 N$
$\Rightarrow 50 = m (g + a)$
$50 = m (10 + 2.45)$
$\Rightarrow m = \frac{50}{12.5}$
$\Rightarrow$ Weight $m g = \frac{50}{12.5} \times 10 = 40 N$

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Q. A body hands from a spring balance supported from the roof of an elevator. If the elevator has an upward acceleration of

2.45 m / s^{2}

, and the balance reads 50 newton's what is the true weight of the body

(g = 9.8 m / s^{2})

Q. A spring balance attached to the roof of a moving elevator indicates

80 kg

weight as the weight of a

120 kg

body. What is the acceleration of the elevation? (Take

g = 10 m / s^{2}

)

Q. A spring balance attached to the roof of a moving elevator indicates

80 kg

weight as the weight of a

120 kg

body. What is the acceleration of the elevation? (Take

g = 10 m / s^{2}

)

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A body hangs from a spring balance supported from the roof of the elevator, the balance reads 50 N when the elevator has an upward acceleration of 2.5 m/s2. What is the true weight of the body? (Take g = 10 m/s2)

The correct option is C 40 N Due to psuedo force T=mg+ma Given, T=50 N ⇒50=m(g+a) 50=m(10+2.45) ⇒m=5012.5 ⇒ Weight mg=5012.5×10=40 N

A body hangs from a spring balance supported from the roof of the elevator, the balance reads $50 N$ when the elevator has an upward acceleration of $2.5 {m/s}^{2}$ . What is the true weight of the body? $($ Take $g$ = $10 {m/s}^{2})$

The correct option is C $40 N$

Due to psuedo force $T = m g + m a$
Given, $T = 50 N$
$\Rightarrow 50 = m (g + a)$
$50 = m (10 + 2.45)$
$\Rightarrow m = \frac{50}{12.5}$
$\Rightarrow$ Weight $m g = \frac{50}{12.5} \times 10 = 40 N$