Question

A body has – 80 micro coulomb of charge. Number of additional electrons in it will be

• A. $8\times {10}^{-5}$
  
• B. $80\times {10}^{-17}$
  
• C. $5\times {10}^{14}$
  
• D. $1.28\times {10}^{-17}$

Answer 1

The correct option is C $5\times {10}^{14}$


By $Q=NeorN=\frac{Q}{e}\therefore N=\frac{80\times {10}^{-6}}{1.6\times {10}^{-19}}=5\times {10}^{14}$