A body has a initial velocity 4 m - s and deceleration of 4 m - s 2- What is the final velocity after travelling 2 m -A- 4 m - sB- 0 m - sC- -3 2 m - sD- 16 m - s

The correct option is B 0 m/sV^2 = U^2 – 2as U = 4 m/s, a = 4 m/s^2 and s = 2 m Substituting the values, we get, V = 0 m/s ...

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Standard IX

Physics

Distance and Displacement

A body has a ...

Question

A body has a initial velocity $4 \frac{m}{s}$ and deceleration of $4 \frac{m}{s^{2}}$ . What is the final velocity after travelling 2 m?

4 m/s

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0 m/s

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√32 m/s

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16 m/s

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Solution

The correct option is B 0 m/s
$V^{2} = U^{2} - 2 a s$

$U = 4 \frac{m}{s}, a = 4 \frac{m}{s^{2}} a n d s = 2 m$

Substituting the values, we get, $V = 0 \frac{m}{s}$

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A body has a initial velocity 4 ms and deceleration of 4 ms2. What is the final velocity after travelling 2 m?

The correct option is B 0 m/sV2= U2 – 2as U= 4 ms, a=4 ms2 and s=2 m Substituting the values, we get, V=0 ms

A body has a initial velocity $4 \frac{m}{s}$ and deceleration of $4 \frac{m}{s^{2}}$ . What is the final velocity after travelling 2 m?

The correct option is B 0 m/s
$V^{2} = U^{2} - 2 a s$

$U = 4 \frac{m}{s}, a = 4 \frac{m}{s^{2}} a n d s = 2 m$

Substituting the values, we get, $V = 0 \frac{m}{s}$