A body has an initial velocity 4 m/s and deceleration of 4 m/ $s^{2}$ then what is the final velocity after travelling 2 m?

4 m/s

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0 m/s

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32 m/s

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16 m/s

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Solution

The correct option is B 0 m/s
$v^{2} = u^{2} + 2 a S$

Initial velocity u = 4 m/s, acceleration a = -4 m/s² and distance S = 2 m,

So, $v^{2} = 4^{2} + 2 \times - 4 \times 2$

$v = 0$

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A body has an initial velocity 4 m/s and deceleration of 4 m/s2 then what is the final velocity after travelling 2 m?

The correct option is B 0 m/sv2=u2+2aS Initial velocity u = 4 m/s, acceleration a = -4 m/s2 and distance S = 2 m, So, v2=42+2×−4×2 v=0

A body has an initial velocity 4 m/s and deceleration of 4 m/ $s^{2}$ then what is the final velocity after travelling 2 m?

The correct option is B 0 m/s
$v^{2} = u^{2} + 2 a S$

Initial velocity u = 4 m/s, acceleration a = -4 m/s² and distance S = 2 m,

So, $v^{2} = 4^{2} + 2 \times - 4 \times 2$

$v = 0$