A body has relative density $7.8$ . What will be its density in M.K.S units?

Open in App

Solution

Step 1: Given data,
The relative density of the body is = $7.8$
We know that the density of water at $4^{\circ} C$ is = $1000 k g / m^{3}$
Step 2: Finding the density of the body,
$r e l a t i v e d e n s i t y = \frac{d e n s i t y o f b o d y}{d e n s i t y o f w a t e r a t 4^{\circ} C} S o, d e n s i t y o f b o d y = r e l a t i v e d e n s i t y \times d e n s i t y o f w a t e r a t 4^{\circ} C = 7.8 \times 1000 k g / m^{3} = 7800 k g / m^{3}$
Hence, the density of the body is $7800 k g / m^{3}$ .

Suggest Corrections

Similar questions

The density of iron is 7.8 $\times 10^{3}$ kg $m^{- 3}$ . What is its relative density ?

The relative density of a metal alloy is $5.6$ . Its density in SI units will be

Join BYJU'S Learning Program