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Question

A body having momentum P is moving in positive x direction. If the direction of velocity is changed by angle 120 from the original direction, find the magnitude of the impulse on the body when it changes its direction.

A
2 P
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B
P2
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C
3 P
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D
3P2
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Solution

The correct option is C 3 P
Let initial momentum be Pi.

Direction of momentum is the same as the direction of velocity.
Direction of initial momentum is +ve x direction.
Pi=P^i
and Pf=Pcos120^i+Psin120^j
=P2^i+3P2^j
Impulse = change in momentum
J=PfPi
=P2^i+3P2^jP^i
=3P2^i+3P2^j
|J|= (32P)2+(32P)2
=3P

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