A body having momentum P is moving in positive x direction. If the direction of velocity is changed by angle 120∘ from the original direction, find the magnitude of the impulse on the body when it changes its direction.
A
√2P
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B
P2
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C
√3P
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D
√3P2
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Solution
The correct option is C√3P Let initial momentum be Pi.
Direction of momentum is the same as the direction of velocity.
Direction of initial momentum is +ve x direction. →Pi=P^i
and −→Pf=Pcos120^i+Psin120^j =−P2^i+√3P2^j
Impulse = change in momentum →J=−→Pf−→Pi =−P2^i+√3P2^j−P^i =−3P2^i+√3P2^j ∴|J|=
⎷(32P)2+(√32P)2 =√3P