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Question

A body initially at 80 degree Celsius cools to 64 degree Celsius in 5 minutes and to 52 degree Celsius in 10 minutes. The temperature of the body after 15 minutes will be.......


Solution

According to Newton law of cooling
θ1θ2t=K[θ1θ22θ0]



For first process : (8064)5=K[80+642θ0] ....(i)
For second process : (8052)10=K[80+522θ0] ....(ii)
For third process : (80θ)15=K[80+θ2θ0] ....(iii)
On solving equation (i) and (ii) we get K=115 and θ0=24C . Putting these values in equation (iii) we get θ=42.7C  
 

Physics

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