A body initially at rest has an acceleration of 10^jm/s2. If the force acting on the body is →F=(2^i+3^j+5^k)N, the instantaneous power at t=5 s will be:
A
100W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150W
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
50W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B150W A body initially at rest has an acceleration of 10^jm/s2.
If the force acting on the body is: F=(2^i+3^j+5^k)N, then the instantaneous power at t = 5seconds will be:
Given: →a=10^jm/s2, →F=(2^i+3^j+5^k)N
And we know that: Power=→F.→v=(2^i+3^j+5^k).(10^j×5)=150W