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Question

A body initially at rest has an acceleration of 10^j m/s2. If the force acting on the body is F=(2^i+3^j+5^k) N, the instantaneous power at t=5 s will be:

A
100W
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B
150W
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C
50W
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D
200W
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Solution

The correct option is B 150W
A body initially at rest has an acceleration of 10^j m/s2.
If the force acting on the body is: F=(2^i+3^j+5^k)N, then the instantaneous power at t = 5seconds will be:
Given: a=10^jm/s2, F=(2^i+3^j+5^k)N

And we know that: Power=F.v=(2^i+3^j+5^k).(10^j×5)=150W

Thus, instantaneous power at t=5 seconds =150 W

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