Question

A body, initially at rest, starts moving with a constant acceleration $2\text{m}/{\text{s}}^2$ . Calculate the distance travelled in 5s.

Answer 1

Given,
As the body starts from rest,
So, Initial Velocity, $u=0\text{m}/\text{s}$
Constant acceleration, $\text{a}=2\text{m}/{\text{s}}^2$
Time, $t=5\text{s}$
For constant acceleration we have the equation,
$S=ut+\frac{1}{2}a{t}^{2}S=0\text{m}/\text{s}\times 5\text{sec}+(\frac{1}{2}\times 2\text{m}/{\text{s}}^2\times (5\text{sec}{)}^2)\Rightarrow S=25\text{m}$

Hence distance travelled in $5\text{sec}$ is $25\text{m}$.