A body is displaced from position A to position B. Kinetic and potential energies of the body at positions A and B are KA=70J,UA=−50J,KB=−20J and UB=30J. Then:
A
Work done by conservative forces is −80J.
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B
Work done by all the forces is −90J.
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C
Work done by non-conservative forces is −10J.
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D
Work done by all the forces is −80J.
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Solution
The correct options are A Work done by conservative forces is −80J. B Work done by all the forces is −90J. C Work done by non-conservative forces is −10J. Work done due to conservative force =− (Change in P.E.) ⇒Wc=−ΔU ⇒Wc=−(UB−UA) ⇒Wc=−(30−(−50) ⇒Wc=−80J Work done by all forces = change in K.E. ⇒Wall=KB−KA ⇒Wall=−20−70 ⇒Wall=−90J Let Wnc be the work done by the other (non-conservative) forces. Wall=−90J ⇒Wc+Wnc=−90 ⇒−80+Wnc=−90 ⇒Wnc=−90+80 ⇒Wnc=−10J Hence, options (a), (b) and (c) are correct.