A body is dropped from a balloon moving up with a velocity of $4 m / s$ when the balloon is at a height of $120.5 m$ from the ground. The height of the body after $5 s$ from the ground is? $(g = 9.8 m s^{- 2})$ .

8 m

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12 m

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18 m

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24 m

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Solution

The correct option is C $18 m$
Given,
$u = 4 m / s$
$g = 9.8 m / s^{2}$
$t = 5 s e c$
$H = 120.5 m$
From 2nd equation of motion,
$- S = u t - \frac{1}{2} g t^{2}$
$- S = 4 \times 5 - \frac{1}{2} \times 9.8 \times 5 \times 5$
$S = - 20 + 122.5 = 102.5 m$
Height of the body after 5 sec,
$h = H - S$
$h = 120.5 - 102.5$
$h = 18 m$
The correct option is C.

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A body is dropped from a balloon moving up with a velocity of 4 m/s when the balloon is at a height of 120.5 m from the ground. The height of the body after 5 s from the ground is? (g=9.8 ms−2).

The correct option is C 18 mGiven,u=4m/sg=9.8m/s2t=5secH=120.5mFrom 2nd equation of motion,−S=ut−12gt2−S=4×5−12×9.8×5×5S=−20+122.5=102.5mHeight of the body after 5 sec,h=H−Sh=120.5−102.5h=18mThe correct option is C.

A body is dropped from a balloon moving up with a velocity of $4 m / s$ when the balloon is at a height of $120.5 m$ from the ground. The height of the body after $5 s$ from the ground is? $(g = 9.8 m s^{- 2})$ .