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Question

A body is dropped from a certain height at time T=0. It undergoes freefall and reaches the ground at time T=t s. What is the expression for the height h from which the body started its free fall?

Acceleration due to gravity is g.


A

h=gt2

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B

h=gt

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C

h=12gt2

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D

h=(12)gt2

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Solution

The correct option is C

h=12gt2


The distance covered with initial velocity u and undergiong constant accleration a in time t is given by:

s=ut+12at2

In this case the distance travelled is h, acceleration is g

We know that h=ut+(12)gt2.

Since the body is initially at rest, u=0.

Therefore, h=(12)gt2


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