A body falls freely from a height of50 m. Simultaneously, another body is thrown from a surface of the earth with a certain initial velocity. The two bodies meet at a height of10 m. What is the initial velocity of the second body?

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A body is dropped from a certain height h and second body is thrown downwards with velocity of 5m/s simultaneously. What will be the differences in heights of two bodies after 3sec.

The correct option is A 15mDistance covered by first ball 0+12×10×32=45Distance covered by second ball 5×3+12×10×33=15+45=60difference in height =15 mHence,option (A) is correct answer.

A body is dropped from a certain height $h$ and second body is thrown downwards with velocity of $5 m / s$ simultaneously $.$ What will be the differences in heights of two bodies after $3 s e c .$

The correct option is A $15 m$
Distance covered by first ball $0 + \frac{1}{2} \times 10 \times 3^{2} = 45$
Distance covered by second ball $5 \times 3 + \frac{1}{2} \times 10 \times 3^{3} = 15 + 45 = 60$
difference in height $= 15$ $m$
Hence,
option $(A)$ is correct answer.