A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

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Solution

The correct option is C
$v = w \sqrt{a^{2} - y^{2}} \Rightarrow 10 = w \sqrt{a^{2} - (4)^{2}}$ and $8 = w \sqrt{a^{2} - (5)^{2}}$
On solving $w = 2 \Rightarrow w = \frac{2 π}{T} = 2 \Rightarrow T = π s e c$

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A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

The correct option is C v=w√a2−y2⇒ 10=w√a2−(4)2 and 8=w√a2−(5)2 On solving w=2 ⇒ w=2πT=2 ⇒ T=π sec

The correct option is C
$v = w \sqrt{a^{2} - y^{2}} \Rightarrow 10 = w \sqrt{a^{2} - (4)^{2}}$ and $8 = w \sqrt{a^{2} - (5)^{2}}$
On solving $w = 2 \Rightarrow w = \frac{2 π}{T} = 2 \Rightarrow T = π s e c$