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Question

A body is executing simple harmonic motion. At a displacement x, its potential energy is E1 and at a displacement y, its potential energy is E2. The potential energy E at a displacement (x+y) is

A
E1+E2
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B
E21+E22
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C
E1+E2+2E1E2
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D
E1E2
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Solution

The correct option is C E1+E2+2E1E2
At displacement x
E1=12mω2x2
or E1=x12mω2
At displacement y
E2=12mω2y2
or E2=y12mω2
At displacement (x+y)
E=12mω2(x+y)2
E=(x+y)12mω2
Hence,
E=E1+E2
E=E1+E2+2E1E2

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