A body is executing simple harmonic motion. At a displacement x, its potential energy is E1 and at a displacement y, its potential energy is E2. The potential energy E at a displacement (x+y) is
A
E1+E2
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B
√E21+E22
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C
E1+E2+2√E1E2
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D
√E1E2
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Solution
The correct option is CE1+E2+2√E1E2 At displacement x E1=12mω2x2
or √E1=x√12mω2
At displacement y E2=12mω2y2
or √E2=y√12mω2
At displacement (x+y) E=12mω2(x+y)2 √E=(x+y)√12mω2
Hence, √E=√E1+√E2 E=E1+E2+2√E1E2