A body is executing simple harmonic motion with an angular frequency $2 r a d / s .$ The velocity of the body at $20$ mm displacement, when the amplitude of motion is $60 m m$ is:

40 m m / s

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60 m m / s

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113 m m / s

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120 m m / s

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Solution

The correct option is C $113 m m / s$
Velocity of SHM particle $v = ω \sqrt{(a^{2} - y^{2})} = 2 \sqrt{60^{2} - 20^{2}} = 113 m m / s$

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A body is executing simple harmonic motion with an angular frequency 2 rad/s. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm is:

The correct option is C 113 mm/sVelocity of SHM particle v=ω√(a2−y2)=2√602−202=113 mm/s

A body is executing simple harmonic motion with an angular frequency $2 r a d / s .$ The velocity of the body at $20$ mm displacement, when the amplitude of motion is $60 m m$ is:

The correct option is C $113 m m / s$
Velocity of SHM particle $v = ω \sqrt{(a^{2} - y^{2})} = 2 \sqrt{60^{2} - 20^{2}} = 113 m m / s$