A body is falling under gravity from rest. When it loses gravitational potential energy by U, its speed is v. The mass of the body shall be

$\frac{2 U}{v}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{U}{2 v}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{2 U}{v^{2}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{U}{2 v^{2}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$\frac{2 U}{v^{2}}$

According to the Law of conservation of energy,
Loss in potential energy = gain in kinetic energy $\Rightarrow U = \frac{1}{2} m v^{2} ∴ m = \frac{2 U}{v^{2}}$

Suggest Corrections

Similar questions

Q. A body is dropped from a certain height in the effect of conservative forces only. When it loses

^{'} U^{'}

amount of potential energy, it subsequently acquires a velocity

^{'} v^{'}

. The mass of the body is

Q. A body is dropped from a certain height. When it loses

U

amount of its energy it acquires a velocity

^{'} v^{'}

. The mass of the body is :

Show that the sum of kinetic energy and potential energy(i.e., total mechanical energy) is always conserved in the case of freely falling body under gravity (with air resistance neglected) from a height h by finding it when (i) the body is at the top, (ii) the body has fallen a distance x, (iii) the body has reached the ground.

(a) Work is said to be done by a force only when _________

(b) Work done = Force $\times$ _________

(d) The S.I. unit of energy is ______

(e) The potential energy of a body is due to its ______ and kinetic energy of body is due to its ______

(f) Gravitational potential energy U = mass $\times$ force of gravity on unit mass $\times$ _________

(g) Kinetic energy = $\frac{1}{2} \times m a s s \times$ _________

(h) Power P = ______ / time taken.

(i) The S. I. unit of power is ______

(j) 1 H.P. = ______ W

Q. A body falls freely under gravity from rest. Name the kind of energy it will possess.
(a) at the point Boni where it falls.
(b) while falling.
(c) on reaching the mound.

Join BYJU'S Learning Program

A body is falling under gravity from rest. When it loses gravitational potential energy by U, its speed is v. The mass of the body shall be

The correct option is C 2Uv2 According to the Law of conservation of energy, Loss in potential energy = gain in kinetic energy ⇒U=12mv2 ∴m=2Uv2

The correct option is C
$\frac{2 U}{v^{2}}$

According to the Law of conservation of energy,
Loss in potential energy = gain in kinetic energy $\Rightarrow U = \frac{1}{2} m v^{2} ∴ m = \frac{2 U}{v^{2}}$