A body is floating in a beaker filled with water. 1/3rd of the body is inside the water and 2/3rd is in the air as shown in the figure. What will be the density of the body. ρw=Density of water ρb=Density of the body [3marks]
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Solution
It is given that 1/3rd of the body is submerged in the water.
So, the volume of displaced water, Vw=V3
where V= Volume of the body
Using Archimedes' principle, the weight of the body is equal to the weight of water displaced by the body. [1mark]
Wb=Ww
⟹ρbVg=ρwVwg
⟹ρbV=ρwV3
⟹ρb=ρw3
Hence, the density of the body is 1/3rd of the density of the water in the container. [2marks]