A body is floating in water, its apparent weight is equal to

Actual weight of the body

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Unity

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Weight of the body minus weights in liquid

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None

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Solution

The correct option is C None
Let the volume of body immersed in water be $V^{}$

Then, buoyant force is $B = ρ g V^{}$

But, as the body is floating and in equilibrium, $B = W$

Apparent weight $W^{'} = W - B = 0$

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