A body is floating in water such that 6 out of 10 parts of its volume is under water. Its density is

0.6 g m / c c

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600 k g / m^{3}

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b o t h

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n o n e

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Solution

The correct option is B $600 k g / m^{3}$
Given,
Raito of volume of water displaced and volume of body, $\frac{V_{w}}{V_{b}} = \frac{6}{10}$
Density of water, $ρ_{w} = 1000 k g / m^{3}$
Weight of body = buoyancy force = weight of water displace
$ρ_{b} V_{b} g = ρ_{w} V_{w} g$
$ρ_{b} = ρ_{w} \frac{V_{w}}{V_{b}} = 1000 \times \frac{6}{10} = 600 k g / m^{3}$
Hence, density of body is $600 k g / m^{3}$

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