A body is having a charge of 10 C. When it comes in contact with an charged body then it loses-1.6C of charge. Find the number of electrons lost.

1.6 × 10^–19

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1.6 × 10¹⁹

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10¹⁹

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–10¹⁹

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Solution

The correct option is C
10¹⁹

We know Q = ne^– from our childhood memories!

Lost charge = -1.6 C

Hence $- 1.6 = n \times (- 1.6 \times 10^{- 19} C)$

$n = 10^{19}$

Implies the body lost $10^{19}$ electrons to the unchanged body.

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A body is having a charge of 10 C. When it comes in contact with an charged body then it loses-1.6C of charge. Find the number of electrons lost.

The correct option is C 1019 We know Q = ne– from our childhood memories! Lost charge = -1.6 C Hence −1.6=n×(−1.6×10−19C) n=1019 Implies the body lost 1019 electrons to the unchanged body.

The correct option is C
10¹⁹

We know Q = ne^– from our childhood memories!

Lost charge = -1.6 C

Hence $- 1.6 = n \times (- 1.6 \times 10^{- 19} C)$

$n = 10^{19}$

Implies the body lost $10^{19}$ electrons to the unchanged body.