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Question

A body is in SHM with period T when oscillated from a freely suspended spring.If this spring is cut in two parts of length ratio 1:3 & again oscillated from the two parts separately,then the periods are T1 & T2 then T1T2 is given as 1x. Find x.

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Solution

Time period is inversely proportional to square root of spring constants.
Spring constant is inversely proportional to the length of spring.
L1L2=13=k2k1
So T1T2=k2k1=13

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