A body is moving vertically upwards. Its velocity changes at a constant rate from $50 m s^{- 1}$ to $20 m s^{- 1}$ in 3 s. What is its acceleration ?

- 30 m s^{- 2}

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- 10 m s^{- 2}

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10 m s^{- 2}

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30 m s^{- 2}

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Solution

The correct option is C $- 10 m s^{- 2}$
Acceleration, $a = \frac{F i n a l V e l o c i t y - I n i t i a l V e l o c i t y}{T i m e} = \frac{20 m / s - 50 m / s}{3 s} = - 10 m / s^{2}$

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A body is moving vertically upwards. Its velocity changes at a constant rate from 50ms−1 to 20ms−1 in 3 s. What is its acceleration ?

The correct option is C −10ms−2Acceleration, a=FinalVelocity−InitialVelocityTime=20m/s−50m/s3s=−10m/s2

A body is moving vertically upwards. Its velocity changes at a constant rate from $50 m s^{- 1}$ to $20 m s^{- 1}$ in 3 s. What is its acceleration ?

The correct option is C $- 10 m s^{- 2}$
Acceleration, $a = \frac{F i n a l V e l o c i t y - I n i t i a l V e l o c i t y}{T i m e} = \frac{20 m / s - 50 m / s}{3 s} = - 10 m / s^{2}$