A body is moving with a speed 0.3 m/sec. To measure its speed with an accuracy of 1% using a sampling distance 3 mm, find the least count that the measuring clock must have ?

10^{- 4} sec

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10^{- 3} sec

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10^{- 2} sec

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10^{- 5} sec

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Solution

The correct option is B $10^{- 4} sec$
$0.3 = \frac{3 \times 10^{- 3}}{t} \Rightarrow t = 10^{- 2}$ sec
$\frac{Δ t}{t} = \frac{1}{100} \Rightarrow Δ t = 10^{- 4}$ sec

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A body is moving with a speed 0.3 m/sec. To measure its speed with an accuracy of 1% using a sampling distance 3 mm, find the least count that the measuring clock must have ?

The correct option is B 10−4sec0.3=3×10−3t⇒t=10−2 secΔtt=1100⇒Δt=10−4 sec

The correct option is B $10^{- 4} sec$
$0.3 = \frac{3 \times 10^{- 3}}{t} \Rightarrow t = 10^{- 2}$ sec
$\frac{Δ t}{t} = \frac{1}{100} \Rightarrow Δ t = 10^{- 4}$ sec