If a body is thrown up with an initial velocity $u$ and covers a maximum height of $h$ , then $h$ is equal to $\frac{u^{2}}{2 g}$ . [ $g$ is the acceleration due to gravity]

Q. Check the accuracy of relation

v^{2} - u^{2} = 2 a s

, where

v

and

u

are final and initial velocities,

a

is the acceleration, and s is the distance.

If a body is thrown up with an initial velocity $u$ and covers a maximum height of h, then h is equal to $\frac{u^{2}}{2 g}$ .

Join BYJU'S Learning Program

A body is moving with an initial velocity of u and having constant acceleration a. The final velocity v can be obtained by using which of the following equation of motion if a body covers a distance s.

The correct option is C v2=u2+2as Given, acceleration=a, initial velocity=u, and distance travelled=s. We can get the final velocity v by using the third equation of motion, v2=u2+2as.

A body is moving with an initial velocity of $u$ and having constant acceleration $a$ . The final velocity $v$ can be obtained by using which of the following equation of motion if a body covers a distance $s$ .

The correct option is C
$v^{2} = u^{2} + 2 a s$

Given, acceleration $= a$ , initial velocity $= u$ , and distance travelled $= s$ .

We can get the final velocity $v$ by using the third equation of motion, $v^{2} = u^{2} + 2 a s$ .