A body is moving with velocity $30 {m s}^{- 1}$ towards east. After $10 s$ its velocity becomes $40 {m s}^{- 1}$ towards north. The average acceleration of the body is:

7 {m s}^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{7} {m s}^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 {m s}^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 {m s}^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is A $1 {m s}^{- 2}$
Average acceleration = change in velocity/ time

$a_{a v} = \frac{40 - 10}{10} = 1 m s^{- 2}$
hence, average acceleration is $1 m s^{- 2}$

Suggest Corrections

Similar questions

30 m s^{- 1}

10 s

40 m s^{- 1}

5 {ms}^{- 1}

25 {ms}^{- 1}

5 s

5 m s^{- 1}

5 m s^{- 1}

Join BYJU'S Learning Program