Question

# A body is orbiting around the earth at mean radius 9 times as great as the orbit of a geostationary satellite. In how many days it will complete one revolution around the earth and what is its angular velocity?

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Solution

## (T21/T22)=(R31/R32)⇒T22=(R2R1)T21⇒T2=(R2R1)3/2T1For the geostationary satellite, T1=1 day(24 hrs.)∴T2=(9RR)32=27 daysSo it will complete one revolution in 27 daysω=2π/T2=2π27×24×3600rad/s2.693×10−6rad/sec.

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