A body is pivoted at a point. A force of $20 N$ is applied at a distance of $20 c m$ from the pivot. Calculate the moment of force about the pivot.

$2 N m$

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$4 N m$

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$6 N m$

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$8 N m$

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Solution

The correct option is B
$4 N m$

Given,
Force $F$ = $20 N$
Perpendicular distance between line of action of force and axis of rotation $r$ = $20 c m = 0.2 m$
Moment of force= $F \times r = 20 \times 0.2 = 4 N m$ (anti-clockwise)

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A body is pivoted at a point. A force of 20 N is applied at a distance of 20 cm from the pivot. Calculate the moment of force about the pivot.

The correct option is B 4 Nm Given, Force F = 20 N Perpendicular distance between line of action of force and axis of rotation r = 20 cm = 0.2 m Moment of force= F×r = 20×0.2=4 N m(anti-clockwise)

A body is pivoted at a point. A force of $20 N$ is applied at a distance of $20 c m$ from the pivot. Calculate the moment of force about the pivot.

The correct option is B
$4 N m$

Given,
Force $F$ = $20 N$
Perpendicular distance between line of action of force and axis of rotation $r$ = $20 c m = 0.2 m$
Moment of force= $F \times r = 20 \times 0.2 = 4 N m$ (anti-clockwise)