A body is pivoted at a point. A force of $50 N$ is applied at a distance of $60 c m$ from the pivot. Calculate the moment of force.

10 N m

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50 N m

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30 N m

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2 N m

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Solution

The correct option is C $30 N m$
Given $F = 50 N, r = 60 c m = 0.6 m$
Moment of force $= F \times r$
$= 50 N \times 0.6 m$
$= 30 N m$

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A body is pivoted at a point. A force of 50N is applied at a distance of 60cm from the pivot. Calculate the moment of force.

The correct option is C 30NmGiven F=50N,r=60cm=0.6mMoment of force =F×r =50N×0.6m =30Nm

A body is pivoted at a point. A force of $50 N$ is applied at a distance of $60 c m$ from the pivot. Calculate the moment of force.

The correct option is C $30 N m$
Given $F = 50 N, r = 60 c m = 0.6 m$
Moment of force $= F \times r$
$= 50 N \times 0.6 m$
$= 30 N m$