A body is placed on an inclined plane. The coefficient of friction between the body and the plane is μ. The plane is gradually tilted up. If θ is the inclination of the plane, then frictional force on the body is
A
constant upto θ=tan−1(μ) and decrease after that
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B
increases upto θ=tan−1(μ)and decrease after that
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C
decreases upto θ=tan−1(μ) and constant after that
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D
Increases upto θ=tan−1(μ) and constant after that
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Solution
The correct option is D Increases upto θ=tan−1(μ) and constant after that As θ increases, frictional force (f=mgsinθ) will increase upto limiting value and then remains constant (becomes kinetic friction)