Question

A body is projected at an angle of ${45}^0$ with a velocity of $20m/s$. What will be its horizontal range?

Answer 1

Given that,

Angle $\theta ={45}^0$

Velocity $u=20m/s$

Now, the horizontal range

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{20\times 20\times 1}{10}$

$R=40m$

Hence, the range is $40m$