MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Distance and Displacement

A body is pro...

Question

A body is projected at an angle of 60^° with horizontal with a speed of 40m/s The speed of the body when velocity becomes perpendicular to initial velocity is(g=10m/s² 1.20\surd3m/s 2.40/\surd3m/s 3.20m/s 4.30m/

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. A particle is projected with speed

10 m / s

60

with horizontal. Then the time after which it's speed becomes half of the initial(g=10m/s^2)

Q. A body is projected with an initial velocity 20 m/s at

60^{\circ}

to the horizontal. Its initial velocity vector is _______

(g = 10 m / s^{2})

Q. A body is projected at an angle

53^{0}

with velocity of 50

m s^{- 1}

. Calculate the time when speed becomes 4/5 of initial velocity.

Q. A body is projected with a velocity of

60 m / s

30^{0}

to horizontal :

Q. A particle is projected with speed

10 m / s

60^{o}

with the horizontal. Then the time after which its speed becomes half of initial is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Distance and Displacement

PHYSICS

Watch in App

explore_more_icon

Explore more

Distance and Displacement

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon