Question

A body is projected at an angle of ${60}^{\circ }$ with the horizontal with momentum P. At its highest point the magnitude of the momentum is :

• A. $\frac{\sqrt{3}}{2}P$
• B. $\frac{2}{\sqrt{3}}P$
• C. $\frac{P}{2}$
• D. P

Answer 1

The correct option is C $\frac{P}{2}$

At the highest point of projectile motion the final vertical velocity is zero$.$

$\therefore P_{vertical}=0$

but $P_{horizontal}=P\cos {60}^0=P\times \frac{1}{2}$

$\therefore$ the magnitude of momentum at the highest point is $\frac{P}{2}$

Hence,

option $\left(C\right)$ is correct answer.