A body is projected at angle 30- to horizontal with a velocity 50 ms-1- Its time of flight is - g-10 m-s2

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Dimensional Analysis

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Question

A body is projected at angle $30^{\circ}$ to horizontal with a velocity 50 $m s^{- 1}$ . Its time of flight is : $(g = 10 m / s^{2})$

4 s

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5 s

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Solution

The correct option is B $5 s$
Given,
$θ = 30^{0}$
$u = 50 m / s$
$g = 10 m / s^{2}$
Time of flight in projectile motion,
$T = \frac{2 u s i n θ}{g}$
$T = \frac{2 \times 50 \times s i n 30^{0}}{10}$
$T = \frac{2 \times 50 \times 0.5}{g}$
$T = 5 s e c$
The correct option is B.

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A body is projected at angle 30∘ to horizontal with a velocity 50 ms−1. Its time of flight is : (g=10m/s2)

The correct option is B 5sGiven,θ=300u=50m/sg=10m/s2Time of flight in projectile motion,T=2usinθgT=2×50×sin30010T=2×50×0.5gT=5secThe correct option is B.

A body is projected at angle $30^{\circ}$ to horizontal with a velocity 50 $m s^{- 1}$ . Its time of flight is : $(g = 10 m / s^{2})$

The correct option is B $5 s$
Given,
$θ = 30^{0}$
$u = 50 m / s$
$g = 10 m / s^{2}$
Time of flight in projectile motion,
$T = \frac{2 u s i n θ}{g}$
$T = \frac{2 \times 50 \times s i n 30^{0}}{10}$
$T = \frac{2 \times 50 \times 0.5}{g}$
$T = 5 s e c$
The correct option is B.