A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq 0$ .

0 \leq θ \leq \frac{π}{4}

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\frac{π}{4} \leq θ \leq \frac{π}{2}

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0 \leq θ \leq \frac{π}{6}

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for no value of

θ

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Solution

The correct option is B if $\frac{π}{4} \leq θ \leq \frac{π}{2}$
Horizontal component of velocity $= 4 G$
vertical component is $= 4 sin θ - g^{2}$
Equal when $4 G o = 4 sin θ - g t$
$g t = 4 (sin θ - cos θ)$
so it $θ > \frac{n}{4}$ $t > 0$ Means situation is possible

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A body is projected at time t=0 with a velocity u at an angle θ with the horizontal. The horizontal and vertical components of its velocity will become equal at time t≠0.

The correct option is B if π4≤θ≤π2Horizontal component of velocity =4 Gvertical component is =4sinθ−g2Equal when 4Go=4sinθ−gtgt=4(sinθ−cosθ)so it θ>n4 t>0 Means situation is possible

A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq 0$ .

The correct option is B if $\frac{π}{4} \leq θ \leq \frac{π}{2}$
Horizontal component of velocity $= 4 G$
vertical component is $= 4 sin θ - g^{2}$
Equal when $4 G o = 4 sin θ - g t$
$g t = 4 (sin θ - cos θ)$
so it $θ > \frac{n}{4}$ $t > 0$ Means situation is possible