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Relative Velocity

A body is pro...

Question

A body is projected from ground speed 20m/s at angle 60? above horizontal. Radius of curvature of its path at the highest point is (g = 10 m/s?)
(1) 1 m
(2) 10 m
(3) 100 m
(4) 1000m

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Solution

Dear Student ,
$H e r e i n t h i s c a s e f r o m t h e g i v e n d a t a w e c a n w r i t e t h a t, V e l o c i t y a t t h e t o p m o s t p o i n t, V_{x} = V \cos θ = V \cos 60 ° = \frac{20}{2} = 10 m / s A g a i n, a s w e k n o w t h a t, a_{n} = \frac{{V_{x}}^{2}}{ρ} w h e r e ρ = r a d i u s o f c u r v a t u r e a n d a_{n} = n o r m a l a c c e l e r a t i o n . S o, w e g e t t h a t, ρ = \frac{{V_{x}}^{2}}{a_{n}} = \frac{10^{2}}{10} = 10 m$

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