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Question

A body is projected from the ground for horizontal range 100 m. At the highest point of its path it breaks apart into two identical part P and Q. If P comes to rest, than the horizontal distance of the landing point of part Q, from the point of projection is:

A
200 m
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B
250 m
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C
150 m
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D
50 m
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Solution

The correct option is C 150 m
As there is no external force acting on the system
If the body wouldn't break into 2 pieces it would land at a distance of 100 m
Then its center of mass would be at 100 m
Even if the body breaks the center of mass of the system should remain at 100 m
As one of the pieces falls down vertically it reaches 50 m
2m(100)=m(50)+mx
x=150m

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