A body is projected from the ground with a velocity v-3- -10- ms-1- The maximum height attained and the range of the body respectively are given g-10 ms-2

The correct option is A 5 m and 6 m Given v⃗=(3î +10ĵ )ms^ 1 ⇒ v _ x =3; v _ y =10 ∴ Maximum height attained H= v _ y ^ 2 2g ...

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Byju's Answer

Standard XII

Physics

Horizontal and Vertical Components of Projectile Motion

A body is pro...

Question

A body is projected from the ground with a velocity $\to v = (3^i + 10^j) m s^{- 1}$ . The maximum height attained and the range of the body respectively are (given $g = 10 m s^{- 2}$ )

5 m

and

6 m

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3 m

and

10 m

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6 m

and

5 m

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3 m

and

5 m

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Solution

The correct option is A $5 m$ and $6 m$
Given $\to v = (3^i + 10^j) m s^{- 1}$

$\Rightarrow v_{x} = 3; v_{y} = 10$

$∴$ Maximum height attained $H = \frac{v_{y}^{2}}{2 g} = \frac{10 \times 10}{2 \times 10} = 5 m$

Range $= v_{x} \times T = v_{x} \times \frac{v_{y}}{2 g} = \frac{3 \times 2 \times 10}{10} = 6 m$

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Point F is 10 m to the South of E.
Point G is 3 m to the East of G.
Point H is 5 m to the South of G.
Point I is 6 m to the West of H.
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Q. Simplify : Add

5 m, (3 m - 5)

and

{6 m}^{2} - 13 m

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A body is projected from the ground with a velocity →v=(3^i+10^j)ms−1. The maximum height attained and the range of the body respectively are (given g=10 ms−2)

The correct option is A 5 m and 6 mGiven →v=(3^i+10^j)ms−1⇒vx=3;vy=10∴ Maximum height attained H=v2y2g=10×102×10=5 mRange =vx×T=vx×vy2g=3×2×1010=6 m

A body is projected from the ground with a velocity $\to v = (3^i + 10^j) m s^{- 1}$ . The maximum height attained and the range of the body respectively are (given $g = 10 m s^{- 2}$ )