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Escape Velocity

A body is pro...

Question

A body is projected from the surface of the earth with the speed 4\sqrt{gR}, then its interstellar speed is (Where R is the radius of the earth)

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Similar questions

Q. If a body is projected with speed v greater than escape speed

v_{e}

from the surface of earth, find its speed in interstellar space.

Q. An object is projected vertically upward with speed

\sqrt{g R},

where R is radius of earth and g is acceleration due to gravity on surface of earth, Find the maximum attained by it.

Q. A rocket is accelerated to speed

v = 2 \sqrt{g R}

near the earth's surface (

R =

radius of earth). Show that very far from earth its speed will be

v = 2 \sqrt{g R}

.

Q. A particle is projected vertically upward from the surface of the earth with a speed of

\sqrt{\frac{3}{2} g R}

R

being the radius of the earth and g is the acceleration due to gravity on the surface of the earth. Then the maximum height ascended is (neglect cosmic dust resistance)

Q. The minimum speed with which a body is projected from the surface of the earth so that it reaches to the surface of the moon is v while the minimum speed with which a body is projected from the surface of the moon so that it reaches to the surface of the earth is v'. Then, disregarding the spinning and orbital motions of the earth and the moon, and using the fact that

\frac{M_{E}}{R_{E}} > \frac{M_{M}}{R_{M}}

M_{E}, M_{M}, R_{E}

R_{M}

are mass of earth, mass of moon, radius of earth and radius of the moon respectively, we can say that :

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